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DECLARE @roomid AS VARCHAR(10), @seats AS INT, @eventid AS INT, @attendees AS INT; DECLARE @Events AS TABLE(eventid INT, attendees INT); DECLARE @Result AS TABLE(roomid VARCHAR(10), eventid INT); -- Step 1: Descending DECLARE CRoomsDesc CURSOR FAST_FORWARD FOR SELECT roomid, seats FROM dbo.Rooms ORDER BY seats DESC, roomid DESC; DECLARE CEventsDesc CURSOR FAST_FORWARD FOR SELECT eventid, attendees FROM dbo.Events ORDER BY attendees DESC, eventid DESC; OPEN CRoomsDesc; OPEN CEventsDesc; FETCH NEXT FROM CRoomsDesc INTO @roomid, @seats; WHILE @@FETCH_STATUS = 0 BEGIN FETCH NEXT FROM CEventsDesc INTO @eventid, @attendees; WHILE @@FETCH_STATUS = 0 AND @seats < @attendees FETCH NEXT FROM CEventsDesc INTO @eventid, @attendees; IF @@FETCH_STATUS = 0 INSERT INTO @Events(eventid, attendees) VALUES(@eventid, @attendees); ELSE BREAK; FETCH NEXT FROM CRoomsDesc INTO @roomid, @seats; END CLOSE CRoomsDesc; CLOSE CEventsDesc;

try { // If the user requested action is menu, then get the menu. String action = req.getParameter("action"); if ( action.equals("menu") ) { ApplicationMenu menu = ApplicationMenu.getInstance(); Document menuDoc = menu.getMenu(); req.setAttribute( "outputDoc", menuDoc ); req.setAttribute( "stylesheet", config/mydomain/applications/book/menu.xsl" ); } // If the user requested action is update, then have the BugAccessorBean // update the list. String machineName = req.getParameter( "machine" ); if ( action.equals("update") ) { ComponentLocator cl = ComponentLocator.getInstance(); Central BugAccessorHome bHome = point for (BugAccessorHome) locating cl.getBeanHome("examples.chapter6.BugAccessor"); services BugAccessor bugBean = bHome.create(); Document detailDoc Communicates = bugBean.updateBugList( machineName );

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DEALLOCATE CRoomsDesc; DEALLOCATE CEventsDesc; -- Step 2: Ascending DECLARE CRooms CURSOR FAST_FORWARD FOR SELECT roomid, seats FROM Rooms ORDER BY seats, roomid; DECLARE CEvents CURSOR FAST_FORWARD FOR SELECT eventid, attendees FROM @Events ORDER BY attendees, eventid; OPEN CRooms; OPEN CEvents; FETCH NEXT FROM CEvents INTO @eventid, @attendees; WHILE @@FETCH_STATUS = 0 BEGIN FETCH NEXT FROM CRooms INTO @roomid, @seats; WHILE @@FETCH_STATUS = 0 AND @seats < @attendees FETCH NEXT FROM CRooms INTO @roomid, @seats; IF @@FETCH_STATUS = 0 INSERT INTO @Result(roomid, eventid) VALUES(@roomid, @eventid); ELSE BEGIN RAISERROR('Not enough rooms for events.', 16, 1); BREAK; END FETCH NEXT FROM CEvents INTO @eventid, @attendees; END CLOSE CRooms; CLOSE CEvents; DEALLOCATE CRooms; DEALLOCATE CEvents; SELECT roomid, eventid FROM @Result;

The algorithm has two phases: 1. Use logic similar to the previous algorithm to match events to rooms, but scan both in descending order to assure the largest events can find rooms . Store the eventids that found a room in a table variable (@Events) . At this point, you have the list of events you can fit that produce the highest revenue, but you also have the least efficient room utilization, meaning the highest possible costs . However, the purpose of the first step was merely to figure out the most profitable events that you can accommodate . 2. The next step is identical to the algorithm in the previous problem with one small revision: declare the CEvents cursor against the @Events table variable and not against the real Events table . By doing this, you end up with the most efficient room utilization for this set of events .

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Inside Microsoft SQL Server 2008: T-SQL Programming Rooms Events 2 48 6 48 4 98 1 203 3 212 5 892 R101 40 R104 40 R203 50 R302 55 R303 55 B102 100 R202 100 B301 600 No Match Match Room Room Rooms R101 40 R104 40 R203 50 R302 55 R303 55 B102 100 R202 100 B301 600

req.setAttribute( "outputDoc", detailDoc ); req.setAttribute( "stylesheet", "config/mydomain/applications/book/bugs.xsl" ); } // If the user requested action is detail, then get the list detail. // for the specified machine. if ( action.equals("detail") ) { SAXBuilder sBuilder = new SAXBuilder(); Document detailDoc = sBuilder.build(new File( "config/mydomain/applications/book/" + machineName + ".xml")); req.setAttribute( "outputDoc", detailDoc ); req.setAttribute( "stylesheet", "config/mydomain/applications/book/bugs.xsl" ); } } ... } ... }

I d like to thank my good friend, Fernando G . Guerrero, who suggested ways to improve and optimize the algorithms for this class of problems . If you re up for challenges, try to look for ways to solve these problems with set-based solutions . Also, try to think of solutions when adding another layer of complexity . Suppose each event has a revenue value stored with it that does not necessarily correspond to the number of attendees . Each room has a cost stored with it that does not necessarily correspond to its capacity . Again, you have no guarantee that there will be enough rooms to host all events . The challenge is to find the most profitable solution .

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