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You should first create an array, holding the color for each pixel in the image: int textureWidth = 512; int textureHeight = 512; Color[] textureColors = new Color[textureWidth* textureHeight]; int i = 0; for (int ver = 0; ver < textureHeight; ver++) for (int hor=0; hor<textureWidth; hor++) { float red = (float)hor / (float)textureWidth; float green = 0; float blue = (float)ver / (float)textureHeight; float alpha = 1; textureColors[i++] = new Color(new Vector4(red, green, blue, alpha)); } This will first create an array that can store colors for a texture with a resolution of 512 512 pixels. Next, the code fills each pixel separately using the double for loop. Using this filling order, you start at the top-left corner. When incrementing the index, the pixels are scanned from left to right and then from top to bottom. Finally, you need to actually create the texture and load the contents of your array into the texture s memory:

site identifier. It and ORACLE_HOME (where the Oracle software is installed) are hashed together in UNIX to create a unique key name for creating or attaching a Shared Global Area (SGA) memory region. If your ORACLE_SID or ORACLE_HOME is not set correctly, you ll get the ORACLE NOT AVAILABLE error, since you can t attach to a shared memory segment that is identified by this unique key. On Windows, shared memory isn t used in the same fashion as on UNIX, but the SID is still important. You can have more than one database under the same ORACLE_HOME, so you need a way to uniquely identify the instance associated with each one, along with their configuration files.

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Since UndoableBase is an implementation of n-level undo capability, each object could end up storing a number of snapshots. As each undo or accept operation occurs, it gets rid of the most recently stored snapshot; this is the classic behavior of a stack data structure. Fortunately, the .NET Framework includes a prebuilt Stack(Of T) class that implements the required functionality. It is declared as follows: <NotUndoable()> _ Private _stateStack As New Stack(Of Byte())() This field is marked as NotUndoable to prevent taking a snapshot of previous snapshots. CopyState() should just record the fields that contain actual business data. Once a snapshot has been taken of the object s data, the snapshot is serialized into a single byte stream. That byte stream is then put on the stack. From there, it can be retrieved and deserialized to perform an undo operation if needed.

Now for the cluster index on our cluster We need to index the cluster before we can put data in it We could create tables in the cluster right now, but we re going to create and populate the tables simultaneously, and we need a cluster index before we can have any data The cluster index s job is to take a cluster key value and return the block address of the block that contains that key It is a primary key, in effect, where each cluster key value points to a single block in the cluster itself So, when we ask for the data in department 10, Oracle will read the cluster key, determine the block address for that, and then read the data The cluster key index is created as follows: ops$tkyte@ORA11GR2> create index emp_dept_cluster_idx 2 on cluster emp_dept_cluster 3 / Index created.

Assuming that you have built a message-oriented Web service according to the best patterns and practices (as discussed in the following chapters), you can generate a WSDL document by browsing the .asmx file of your Web service, and then clicking the Service Description link in the default client page. This link simply appends WSDL to the URL of the .asmx file. Figure 2-2 shows the default client page for the StockTraderService Web service and the corresponding Service Description link.

The conditional logical operators operate in short-circuit mode, meaning that, if after evaluating Expr1 the result can already be determined, then it skips the evaluation of Expr2. The following code shows examples of expressions in which the value can be determined after evaluating the first operand: bool bVal; bVal = (1 == 2) && (2 == 2); bVal = (1 == 1) || (1 == 2); // False, after evaluating first expression // True, after evaluating first expression

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